Question

the weight m of an object on the moon varies directly as its weight e on earth. a person who weighs 151.65 lb on earth weighs 25.78 lb on the moon. how much would a 228.82 - lb person weigh on the moon? a 228.82 - lb person would weigh lb on the moon. (round to the nearest tenth.)

Explanation:

Step1: Set up the direct - variation equation

Since $M$ varies directly as $E$, we have $M = kE$, where $k$ is the constant of variation. We know that when $E = 151.65$ lb and $M = 25.78$ lb. Substitute these values into the equation: $25.78=k\times151.65$. Then $k=\frac{25.78}{151.65}$.

Step2: Calculate the value of $k$

$k=\frac{25.78}{151.65}\approx0.17$.

Step3: Find the weight on the moon for a 228.82 - lb person

Now we want to find $M$ when $E = 228.82$ lb. Using the equation $M = kE$ and substituting $k\approx0.17$ and $E = 228.82$, we get $M=0.17\times228.82$.
$M = 0.17\times228.82 = 38.9$.

Answer:

$38.9$