QUESTION IMAGE
Question
use the rules for working with measurements to give your answer to the appropriate accuracy and/or precision. find the total amount (area) of paper used for labels for 1,000 cans like the one shown in the figure below (in cm²). 2.27 cm 7.48 cm
Step1: Identify the shape of the label
The label on a can is a rectangle when unrolled, but its area is equivalent to the lateral (curved) surface area of a cylinder. The formula for the lateral surface area of a cylinder is \( A = 2\pi rh \), where \( r \) is the radius and \( h \) is the height. Here, the radius \( r = 2.27 \, \text{cm} \) and the height \( h = 7.48 \, \text{cm} \).
Step2: Calculate the lateral surface area for one can
Substitute \( r = 2.27 \) and \( h = 7.48 \) into the formula:
\( A = 2 \times \pi \times 2.27 \times 7.48 \)
First, calculate \( 2 \times 2.27 = 4.54 \). Then, \( 4.54 \times 7.48 \approx 33.9592 \). Multiply by \( \pi \): \( 33.9592 \times \pi \approx 33.9592 \times 3.1416 \approx 106.63 \, \text{cm}^2 \) (for one can).
Step3: Calculate the total area for 1,000 cans
Multiply the area of one can by 1,000:
\( \text{Total Area} = 106.63 \times 1000 = 106630 \, \text{cm}^2 \) (we check significant figures: the given values \( 2.27 \) (3 sig figs) and \( 7.48 \) (3 sig figs) suggest the answer should have 3 sig figs, but let's verify the calculation more precisely).
Wait, let's recalculate the lateral surface area more accurately:
\( 2 \times \pi \times 2.27 \times 7.48 = 2 \times 7.48 \times 2.27 \times \pi \)
\( 2 \times 7.48 = 14.96 \)
\( 14.96 \times 2.27 = 14.96 \times 2 + 14.96 \times 0.27 = 29.92 + 4.0392 = 33.9592 \)
\( 33.9592 \times \pi \approx 33.9592 \times 3.14159265 \approx 106.631 \, \text{cm}^2 \) per can.
For 1,000 cans: \( 106.631 \times 1000 = 106631 \, \text{cm}^2 \). Rounding to appropriate precision (since the measurements have three significant figures), the total area is approximately \( 1.07 \times 10^5 \) or \( 107000 \)? Wait, no—let's check the multiplication again. Wait, \( 2.27 \) is radius, \( 7.48 \) is height. Let's confirm the formula: lateral surface area of cylinder is \( 2\pi rh \), which is correct.
Wait, maybe I made a mistake in the first calculation. Let's do it step by step with more precision:
\( 2 \times \pi = 6.283185307 \)
\( 6.283185307 \times 2.27 = 6.283185307 \times 2 + 6.283185307 \times 0.27 = 12.56637061 + 1.696460033 = 14.26283064 \)
\( 14.26283064 \times 7.48 = 14.26283064 \times 7 + 14.26283064 \times 0.48 = 99.83981448 + 6.846158707 = 106.6859732 \, \text{cm}^2 \) per can.
Then, for 1,000 cans: \( 106.6859732 \times 1000 = 106685.9732 \, \text{cm}^2 \). Now, considering significant figures: \( 2.27 \) (3 sig figs) and \( 7.48 \) (3 sig figs), so the result should have 3 sig figs. \( 106685.9732 \) rounded to 3 sig figs is \( 1.07 \times 10^5 \) or \( 107000 \)? Wait, \( 106686 \) rounded to 3 significant figures: the first three significant figures are 1, 0, 6? Wait no, 106686: the first non-zero digit is 1, then 0, 6, 6... Wait, no, 106686 is \( 1.06686 \times 10^5 \). To three significant figures, it's \( 1.07 \times 10^5 \) (since the fourth digit is 6, which rounds up the third digit from 6 to 7). So \( 1.07 \times 10^5 = 107000 \, \text{cm}^2 \). Wait, but maybe the problem expects us to use the given numbers as is, without worrying about significant figures, just multiply. Let's recalculate:
\( 2 \times \pi \times 2.27 \times 7.48 \times 1000 \)
First, multiply all the numbers: \( 2 \times 2.27 \times 7.48 \times 1000 \times \pi \)
\( 2 \times 2.27 = 4.54 \)
\( 4.54 \times 7.48 = 33.9592 \)
\( 33.9592 \times 1000 = 33959.2 \)
\( 33959.2 \times \pi \approx 33959.2 \times 3.14159265 \approx 106685.97 \, \text{cm}^2 \)
So the total area is approximately \( 106686 \, \text{cm}^2 \), which can be rounded to \( 107000 \) (3 sig…
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\( 107000 \) (or more precisely \( 106686 \), but with three significant figures, \( 1.07 \times 10^5 \) or \( 107000 \))