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Question
unit test 2 - electronic structure and chem
complete the following electron dot structure.
Step1: Determine the number of valence electrons for oxygen
Oxygen has 6 valence electrons. In the electron - dot structure of \(O_2\), each oxygen atom needs to achieve an octet.
Step2: Calculate the number of bonding pairs
The total number of valence electrons for \(O_2\) is \(6\times2 = 12\). If we assume a double - bond (\(O = O\)), each oxygen has 6 non - bonding electrons and 4 bonding electrons (2 pairs in the double bond). The structure \(\ce{:\overset{..}{O}=\overset{..}{O}:}\) satisfies the octet rule.
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The correct electron - dot structure is the one with a double bond (\(\ce{:\overset{..}{O}=\overset{..}{O}:}\)), so the answer is the option with the double - bond (the middle option in the given choices if we assume the first is single, middle is double and last is triple).