Question

two fruit flies that are heterozygous for body color and eye color are crossed. brown body color is dominant to black body color. red eye color is dominant to brown eye color. use the punnett square to determine the ratio of offspring with the described trait to the total number of offspring: brown body and red eyes \boxed{}:\boxed{} brown body and brown eyes \boxed{}:\boxed{} black body and red eyes \boxed{}:\boxed{} black body and brown eyes \boxed{}:\boxed{} done

Explanation:

Step1: Determine Genotypes

Let body color: \( B \) (brown, dominant), \( b \) (black, recessive). Eye color: \( E \) (red, dominant), \( e \) (brown, recessive). Heterozygous parents: \( BbEe \times BbEe \). Gametes: \( BE, Be, bE, be \) for each.

Step2: Complete Punnett Square

	\( BE \)	\( Be \)	\( bE \)	\( be \)
\( Be \)	\( BBEe \)	\( BBee \)	\( BbEe \)	\( Bbee \)
\( bE \)	\( BbEE \)	\( BbEe \)	\( bbEE \)	\( bbEe \)
\( be \)	\( BbEe \)	\( Bbee \)	\( bbEe \)	\( bbee \)

Step3: Count Phenotypes

• Brown body (B_) and red eyes (E_): \( BBEE, BBEe, BbEE, BbEe, BBEe, BbEe, BbEE, BbEe \) → 9.
• Brown body (B_) and brown eyes (ee): \( BBee, Bbee, Bbee \) → 3.
• Black body (bb) and red eyes (E_): \( bbEE, bbEe, bbEe \) → 3.
• Black body (bb) and brown eyes (ee): \( bbee \) → 1.

Step4: Determine Ratios

Total offspring: \( 16 \). Ratios:

• Brown & red: \( 9:16 \)
• Brown & brown: \( 3:16 \)
• Black & red: \( 3:16 \)
• Black & brown: \( 1:16 \)

Answer:

Brown body and red eyes: \( 9:16 \)
Brown body and brown eyes: \( 3:16 \)
Black body and red eyes: \( 3:16 \)
Black body and brown eyes: \( 1:16 \)