trisha is practicing punnett squares. based on this sample, which box did she not fill out correctly?
options:
d.
a.
b.
c.
(there is a punnett square image with boxes labeled a, b, c, d and genotypes dd, dd, dd, dd etc.)

Question

Accepted Answer

# Explanation:
## Step1: Analyze Punnett Square Rules
In a Punnett square, alleles from one parent are on the top and from the other on the side. Each box is filled by combining the corresponding alleles.
## Step2: Check Each Option
- **Option a**: If the top allele is $D$ and the side allele is $d$, combining them gives $Dd$. This is correct.
- **Option b**: If the top allele is $D$ and the side allele is $D$, combining them gives $DD$. This is correct.
- **Option c**: If the top allele is $d$ and the side allele is $D$, combining them should give $Dd$, but the box has $Dd$ which is correct.
- **Option d**: If the top allele is $d$ and the side allele is $D$, combining them should give $Dd$, but the box has $Dd$ which is correct. Wait, no - wait, re - check. Wait, no, looking at the Punnett square structure. The top row has $a$ and $b$ (assuming $a$ and $b$ are alleles from one parent, say $D$ and $D$), and the left - hand column has $c$ and $d$ (assuming $d$ and $d$). No, actually, standard Punnett square: one parent's alleles on top ($D$ and $d$) and the other's on the side ($D$ and $D$). For the box labeled $d$, if the top allele is $d$ and the side allele is $D$, it should be $Dd$, but in the given Punnett square, the box labeled $d$ has $Dd$ which is correct. Wait, no - no! Wait, no, the problem is mis - labeled. Wait, no, in a Punnett square for $Dd\times DD$ (assuming one parent is $Dd$ and the other is $DD$). The rows and columns: if we have $D$ and $d$ (from $Dd$) on top and $D$ and $D$ (from $DD$) on the side. Then:
    - Top - left: $D\times D = DD$ (but in the given square, $c$ is $Dd$ which is wrong. Wait, no - no, swap. Wait, no, if one parent is $Dd$ (so gametes $D$ and $d$) and the other is $Dd$ (gametes $D$ and $d$) - no, no, the problem is, in a Punnett square, each box is the combination of row and column alleles. If we assume the top alleles are $D$ and $d$ (from one parent) and the side alleles are $D$ and $D$ (from another parent). Then:
        - First row (side $D$): $D\times D=DD$ (should be, but in the given square, $a$ is $Dd$ which is wrong if the side is $D$ and top is $D$. Wait, no - the problem is, the labels. Wait, no - the question is "which box did she NOT fill out correctly". If we assume standard Punnett square rules (row and column alleles combine). If we assume the side has alleles $D$ and $D$ (parent 1) and top has $D$ and $d$ (parent 2). Then:
            - Box $a$: top $D$, side $D$ → $DD$ (but in the square $a$ is $Dd$ → wrong)
            - Box $b$: top $d$, side $D$ → $Dd$ (but in the square $b$ is $DD$ → wrong. Wait, no - no, wait, the user's Punnett square:
                - Looking at the square:
                    - If we consider the rows (side) as $D$ (top row) and $D$ (bottom row), and columns (top) as $d$ (left) and $D$ (right). Then:
                        - Box $c$: column $d$, row $D$ → $Dd$ (correct if parent 1 is $D$ and parent 2 is $d$)
                        - Box $a$: column $d$, row $D$ → $Dd$ (but if columns are $D$ and $d$ (parent 1) and rows are $D$ and $D$ (parent 2). Then box $a$ (column $D$, row $D$) should be $DD$, but in the given square $a$ is $Dd$ → wrong.

# Answer:
A.

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QUESTION IMAGE

Question

Explanation:

Step1: Analyze Punnett Square Rules

Step2: Check Each Option

Answer: