Question

titration example: you neutralize 50.00 ml of a hcl solution with 33.32 ml of a 0.1524 m naoh solution. what is the concentration (m) of the hcl solution?

Explanation:

Step1: Write the chemical reaction equation

The reaction between \(HCl\) and \(NaOH\) is \(HCl + NaOH=NaCl + H_{2}O\). The mole ratio of \(HCl\) to \(NaOH\) is \(n_{HCl}:n_{NaOH}=1:1\).

Step2: Use the formula \(n = c\times V\)

We know that \(n_{HCl}=c_{HCl}\times V_{HCl}\) and \(n_{NaOH}=c_{NaOH}\times V_{NaOH}\). Since \(n_{HCl}=n_{NaOH}\), we have \(c_{HCl}\times V_{HCl}=c_{NaOH}\times V_{NaOH}\).

Step3: Substitute the given values

Given \(V_{HCl} = 50.00\space mL\), \(c_{NaOH}=0.1524\space M\), \(V_{NaOH}=33.32\space mL\). Rearranging the formula \(c_{HCl}=\frac{c_{NaOH}\times V_{NaOH}}{V_{HCl}}\).
Substitute the values: \(c_{HCl}=\frac{0.1524\space M\times33.32\space mL}{50.00\space mL}\)

$$c_{HCl}=\frac{0.1524\times33.32}{50.00}\space M$$

$$c_{HCl}=\frac{5.078928}{50.00}\space M = 0.1016\space M$$

Answer:

The concentration of the \(HCl\) solution is \(0.1016\space M\)