Question

tetrahedral
sp³d
sp
sp³d²
sp²
sp³
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part d
trigonal bipyramidal
sp³d²
sp²
sp
sp³
sp³d

Explanation:

• For a tetrahedral geometry, the hybridization is \(sp^{3}\). In \(sp^{3}\) hybridization, one \(s\) orbital and three \(p\) orbitals mix to form four \(sp^{3}\) hybrid orbitals which are oriented in a tetrahedral geometry (bond - angles of approximately \(109.5^{\circ}\)).
• For a trigonal bipyramidal geometry, the hybridization is \(sp^{3}d\). Here, one \(s\) orbital, three \(p\) orbitals, and one \(d\) orbital mix. The \(sp^{3}d\) hybrid orbitals are arranged in a trigonal bipyramidal geometry (with two types of bond - angles: \(90^{\circ}\) and \(120^{\circ}\)).

Answer:

For tetrahedral: \(sp^{3}\). For trigonal bipyramidal: \(sp^{3}d\).