Question

c) the temperature is ___ °c ___ °f (accompanied by a thermometer image with °f scale on the left (markings: 120, 100, 80, 60, 40, 20, 0, -20, -40) and °c scale on the right (markings: 50, 40, 30, 20, 10, 0, -10, -20, -30, -40), with the mercury level aligned to the 100 °f / 40 °c horizontal line)

Explanation:

Step1: Determine the Celsius temperature

Looking at the Celsius scale (right side), the liquid level aligns with 40°C? Wait, no, wait. Wait, the left is Fahrenheit, right is Celsius? Wait, no, the labels: bottom left is °F, bottom right is °C. Wait, the marks: on the Celsius scale, between 30 and 40? Wait, no, let's check the positions. Wait, the horizontal line is at the Celsius scale: let's see the Celsius scale has marks. Let's count the intervals. Wait, the Celsius scale: from 0 to 10 is some intervals, but wait, the temperature here: looking at the thermometer, the liquid is at the mark where on the Celsius scale, let's see: the right scale (°C) has 0, 10, 20, 30, 40, 50. Wait, the horizontal line is at 40? No, wait, maybe I mixed up. Wait, no, the left is °F (120, 100, 80, etc.), right is °C (50, 40, 30, etc.). Wait, the liquid level is at the intersection of the horizontal line, which on the Celsius scale is at 40? Wait, no, wait, let's check the Fahrenheit and Celsius conversion. Wait, actually, the thermometer shows that the temperature in Celsius: let's see, the mark is at 40? Wait, no, wait, the horizontal line is at the Celsius scale: looking at the right scale, the numbers are 50, 40, 30, 20, 10, 0, -10, etc. The liquid is at the 40 mark? Wait, no, maybe I made a mistake. Wait, actually, the correct way: the Celsius scale here, the liquid is at 40? Wait, no, wait, the Fahrenheit scale: 100°F is equal to 37.78°C, but here the liquid is at 100°F? Wait, no, the left scale is °F, so the liquid is at 100°F? Wait, no, the horizontal line is at the Fahrenheit scale (left) at 100, and on the Celsius scale (right) at 40? Wait, no, that can't be. Wait, no, the thermometer has two scales: left is °F, right is °C. The liquid level is at the same horizontal line, so we need to read both. Wait, looking at the Celsius scale: the marks between 30 and 40? Wait, no, the numbers on the Celsius scale: 50, 40, 30, 20, 10, 0, -10, -20, -30, -40. The liquid is at the 40 mark? Wait, no, the horizontal line is at the Celsius scale's 40? Wait, maybe the Celsius temperature is 40? No, wait, 100°F is 37.78°C, but here the Fahrenheit is 100? Wait, the left scale (°F) has 120, 100, 80, 60, 40, 20, 0, -20, -40. The liquid is at 100°F? Wait, no, the horizontal line is at 100 on the Fahrenheit scale and at 40 on the Celsius scale? Wait, that's incorrect, because 100°F is about 37.78°C. Wait, maybe the thermometer is marked such that the Celsius scale: let's check the intervals. Between 0 and 10°C, how many small marks? Let's see, the Celsius scale: from 0 to 10, there are 10 small marks, so each small mark is 1°C. Wait, the liquid is at the 40 mark? Wait, no, the horizontal line is at the Celsius scale: looking at the right side, the number 40 is there, and the liquid is at that level. Wait, maybe the Celsius temperature is 40? No, that can't be, because 40°C is 104°F. Wait, the Fahrenheit scale here: 100 is marked, and the liquid is at 100°F? Wait, no, the horizontal line is at 100 on the Fahrenheit scale and at 40 on the Celsius scale? That would mean 100°F = 40°C, which is wrong. Wait, I must have misread the scales. Wait, no, the left scale is °F, so the numbers are 120, 100, 80, 60, 40, 20, 0, -20, -40. The right scale is °C, numbers 50, 40, 30, 20, 10, 0, -10, -20, -30, -40. The liquid level is at the same horizontal line, so let's see: on the Celsius scale, the liquid is at 40? No, wait, between 30 and 40? Wait, no, the mark for 40°C is there, and the liquid is at that. Wait, maybe the thermometer is a dual scale, and the correct reading is: Celsius: 40? No, that's not right. Wait, maybe I made a mistake. Wait, let's check the Fahrenheit and Celsius conversion formula: \( F = \frac{9}{5}C + 32 \). If C is 40, then F is \( \frac{9}{5}*40 + 32 = 72 + 32 = 104 \), but the Fahrenheit scale here shows 100. Wait, so maybe the Celsius is 38? No, wait, the marks: on the Celsius scale, between 30 and 40, how many marks? Let's see, the Celsius scale has 50, 40, 30, 20, 10, 0, etc. Each major mark (like 30, 40) is 10°C apart, and between them, how many small marks? Let's count: between 30 and 40, there are 10 small marks, so each is 1°C. So the liquid is at 40°C? But then Fahrenheit would be 104, but the Fahrenheit scale here has 100 at that level. Wait, maybe the thermometer is marked incorrectly, or I misread. Wait, the problem is to read the temperature. Looking at the thermometer, the liquid is at the horizontal line, which on the Celsius scale is at 40? Wait, no, the right scale (°C) has 40 marked, and the liquid is at that. So Celsius is 40? No, wait, the left scale (°F) has 100 marked, and the liquid is at that. So Fahrenheit is 100. Then convert to Celsius: \( C = \frac{5}{9}(F - 32) \). So \( C = \frac{5}{9}(100 - 32) = \frac{5}{9}*68 \approx 37.78 \), but the Celsius scale here shows 40. Maybe the thermometer is a simple one where 100°F is 40°C? No, that's not standard. But according to the diagram, the horizontal line is at 100°F (left) and 40°C (right). So we just read the scales as they are. So the Celsius temperature is 40? Wait, no, maybe the Celsius scale is marked with 40 at that position. So the temperature is 40°C and 100°F? Wait, that must be it. The thermometer has both scales, and the liquid is at 40°C (right scale) and 100°F (left scale). So we just read the values from the scales.

Step2: Confirm the readings

Looking at the Celsius scale (right), the liquid is at the 40 mark, so 40°C. Looking at the Fahrenheit scale (left), the liquid is at the 100 mark, so 100°F.

Answer:

The temperature is \( \boldsymbol{40} \) °C and \( \boldsymbol{100} \) °F.