Question

square roots
\sqrt{36} = ?
(there is a number line with intervals 1&2, 2&3, ..., 9&10 above, and numbers 0,1,2,...,11 below the number line)

Explanation:

Step1: Recall square root definition

The square root of a number \( x \) is a value \( y \) such that \( y^2 = x \). So we need to find \( y \) where \( y^2 = 36 \).

Step2: Find the number whose square is 36

We know that \( 6\times6 = 36 \) (or \( 6^2 = 36 \)), so \( \sqrt{36}=6 \).

Answer:

6