Question

solve the system of equations.
$y = 8x - 7$
$y = 6x + 5$
$x = \square$
$y = \square$

Explanation:

Step1: Set equations equal

Since both equal \( y \), set \( 8x - 7 = 6x + 5 \).

Step2: Solve for \( x \)

Subtract \( 6x \): \( 2x - 7 = 5 \). Add 7: \( 2x = 12 \). Divide by 2: \( x = 6 \).

Step3: Find \( y \)

Substitute \( x = 6 \) into \( y = 8x - 7 \): \( y = 8(6) - 7 = 48 - 7 = 41 \).

Answer:

\( x = 6 \)
\( y = 41 \)