Question

1. $16 + 2b = -2b - 8$

a) ${-2}$ b) ${-6}$
c) ${12}$ d) ${16}$

1. solve the equation.
2. $x + 3 = 6 + 2x$

a) ${3}$ b) ${-9}$
c) ${-13}$ d) ${-3}$

Explanation:

Problem 3:

Step1: Add \(2b\) to both sides

\(16 + 2b + 2b = -2b - 8 + 2b\)
Simplify: \(16 + 4b = -8\)

Step2: Subtract 16 from both sides

\(16 + 4b - 16 = -8 - 16\)
Simplify: \(4b = -24\)

Step3: Divide by 4

\(\frac{4b}{4} = \frac{-24}{4}\)
Simplify: \(b = -6\)

Step1: Subtract \(x\) from both sides

\(x + 3 - x = 6 + 2x - x\)
Simplify: \(3 = 6 + x\)

Step2: Subtract 6 from both sides

\(3 - 6 = 6 + x - 6\)
Simplify: \(-3 = x\)

Answer:

B) \(\{-6\}\)

Problem 4: