Question

solve 3^(3x - 6) = 27
what are the pairs
{ } =

Explanation:

Step1: Simplify the equation

Notice that \(27 = 3^3\), so rewrite the equation \(3^{(3x - 6)}=27\) as \(3^{(3x - 6)} = 3^3\).

Step2: Set exponents equal

Since the bases are the same (\(3\)), we can set the exponents equal to each other: \(3x - 6=3\).

Step3: Solve for \(x\)

Add \(6\) to both sides: \(3x=3 + 6\), so \(3x = 9\). Then divide both sides by \(3\): \(x=\frac{9}{3}=3\).

Answer:

The solution for \(x\) is \(3\), so the pair (if considering \(x\) value) is \(\{x = 3\}\) (assuming the set is for \(x\) solution).