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solve. 16 - 2z < 10z - 20 + 6z

Question

solve. 16 - 2z < 10z - 20 + 6z

Explanation:

Step1: Combine like terms on the right

Simplify \(10z - 20 + 6z\) to \(16z - 20\). The inequality becomes \(16 - 2z < 16z - 20\).

Step2: Add \(2z\) to both sides

Adding \(2z\) gives \(16 < 18z - 20\).

Step3: Add 20 to both sides

Adding 20: \(36 < 18z\).

Step4: Divide by 18

Divide both sides by 18: \(2 < z\) (or \(z > 2\)).

Answer:

\(z > 2\)