QUESTION IMAGE
Question
snc2p chemistry
extra practice
balance the equations below:
- _n₂ + _h₂ → ___nh₃
- _kclo₃ → _kcl + ___o₂
- _nacl + _f₂ → _naf + _cl₂
- _h₂ + _o₂ → ___h₂o
- _pb(oh)₂ + _hcl → _h₂o + _pbcl₂
- _albr₃ + _k₂so₄ → _kbr + _al₂(so₄)₃
- _ch₄ + _o₂ → _co₂ + _h₂o
- _c₃h₈ + _o₂ → _co₂ + _h₂o
- _c₈h₁₈ + _o₂ → _co₂ + _h₂o
- _fecl₃ + _naoh → _fe(oh)₃ + _nacl
- _p + _o₂ → ___p₂o₅
- _na + _h₂o → _naoh + _h₂
- _ag₂o → _ag + ___o₂
- _s₈ + _o₂ → ___so₃
Step1: Balance the first equation
For \(N_2 + H_2
ightarrow NH_3\), balance \(N\) and \(H\) atoms.
$$N_2 + 3H_2 = 2NH_3$$
Step2: Balance the second equation
For \(KClO_3
ightarrow KCl + O_2\), balance \(O\) atoms.
$$2KClO_3 = 2KCl + 3O_2$$
Step3: Balance the third equation
For \(NaCl+F_2
ightarrow NaF + Cl_2\), balance \(Cl\) and \(F\) atoms.
$$2NaCl+F_2 = 2NaF + Cl_2$$
Step4: Balance the fourth equation
For \(H_2+O_2
ightarrow H_2O\), balance \(O\) atoms.
$$2H_2+O_2 = 2H_2O$$
Step5: Balance the fifth equation
For \(Pb(OH)_2+HCl
ightarrow H_2O + PbCl_2\), balance \(Cl\) and \(H\) atoms.
$$Pb(OH)_2 + 2HCl = 2H_2O+PbCl_2$$
Step6: Balance the sixth equation
For \(AlBr_3+K_2SO_4
ightarrow KBr + Al_2(SO_4)_3\), balance \(Al\), \(Br\) and \(SO_4\) groups.
$$2AlBr_3 + 3K_2SO_4 = 6KBr+Al_2(SO_4)_3$$
Step7: Balance the seventh equation
For \(CH_4+O_2
ightarrow CO_2 + H_2O\), balance \(C\), \(H\) and \(O\) atoms.
$$CH_4 + 2O_2 = CO_2+2H_2O$$
Step8: Balance the eighth equation
For \(C_3H_8+O_2
ightarrow CO_2 + H_2O\), balance \(C\), \(H\) and \(O\) atoms.
$$C_3H_8+5O_2 = 3CO_2 + 4H_2O$$
Step9: Balance the ninth equation
For \(C_8H_{18}+O_2
ightarrow CO_2 + H_2O\), balance \(C\), \(H\) and \(O\) atoms.
$$2C_8H_{18}+25O_2 = 16CO_2+18H_2O$$
Step10: Balance the tenth equation
For \(FeCl_3+NaOH
ightarrow Fe(OH)_3 + NaCl\), balance \(Fe\), \(Cl\), \(Na\) and \(OH\) groups.
$$FeCl_3 + 3NaOH = Fe(OH)_3+3NaCl$$
Step11: Balance the eleventh equation
For \(P+O_2
ightarrow P_2O_5\), balance \(P\) and \(O\) atoms.
$$4P + 5O_2 = 2P_2O_5$$
Step12: Balance the twelfth equation
For \(Na+H_2O
ightarrow NaOH + H_2\), balance \(Na\), \(H\) and \(O\) atoms.
$$2Na+2H_2O = 2NaOH + H_2$$
Step13: Balance the thirteenth equation
For \(Ag_2O
ightarrow Ag+O_2\), balance \(Ag\) and \(O\) atoms.
$$2Ag_2O = 4Ag+O_2$$
Step14: Balance the fourteenth equation
For \(S_8+O_2
ightarrow SO_3\), balance \(S\) and \(O\) atoms.
$$S_8+12O_2 = 8SO_3$$
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- \(1\) \(N_2 + 3\) \(H_2 = 2\) \(NH_3\)
- \(2\) \(KClO_3 = 2\) \(KCl + 3\) \(O_2\)
- \(2\) \(NaCl+1\) \(F_2 = 2\) \(NaF + 1\) \(Cl_2\)
- \(2\) \(H_2+1\) \(O_2 = 2\) \(H_2O\)
- \(1\) \(Pb(OH)_2 + 2\) \(HCl = 2\) \(H_2O+1\) \(PbCl_2\)
- \(2\) \(AlBr_3 + 3\) \(K_2SO_4 = 6\) \(KBr+1\) \(Al_2(SO_4)_3\)
- \(1\) \(CH_4 + 2\) \(O_2 = 1\) \(CO_2+2\) \(H_2O\)
- \(1\) \(C_3H_8+5\) \(O_2 = 3\) \(CO_2 + 4\) \(H_2O\)
- \(2\) \(C_8H_{18}+25\) \(O_2 = 16\) \(CO_2+18\) \(H_2O\)
- \(1\) \(FeCl_3 + 3\) \(NaOH = 1\) \(Fe(OH)_3+3\) \(NaCl\)
- \(4\) \(P + 5\) \(O_2 = 2\) \(P_2O_5\)
- \(2\) \(Na+2\) \(H_2O = 2\) \(NaOH + 1\) \(H_2\)
- \(2\) \(Ag_2O = 4\) \(Ag+1\) \(O_2\)
- \(1\) \(S_8+12\) \(O_2 = 8\) \(SO_3\)