Question

simplify.
$(v^{-7})^{-2}$
write your answer without using negative exponents.

Explanation:

Step1: Apply exponent rule

When raising a power to a power, multiply the exponents: \((a^m)^n = a^{m\times n}\). So for \((v^{-7})^{-2}\), we multiply \(-7\) and \(-2\).
\((v^{-7})^{-2}=v^{(-7)\times(-2)}\)

Step2: Calculate the exponent

\((-7)\times(-2) = 14\), so we get \(v^{14}\).

Answer:

\(v^{14}\)