Question

simplify. ((3x^{-6}y^{4})^{3}) write your answer using only positive exponents. your answer your answer is incorrect.

Explanation:

Step1: Apply power - of - a - product rule

$(3x^{-6}y^{4})^{3}=3^{3}\times(x^{-6})^{3}\times(y^{4})^{3}$

Step2: Calculate $3^{3}$

$3^{3}=27$

Step3: Apply power - of - a - power rule for $x$ and $y$ terms

$(x^{-6})^{3}=x^{-18}$ and $(y^{4})^{3}=y^{12}$

Step4: Rewrite with positive exponent for $x$

$x^{-18}=\frac{1}{x^{18}}$, so the expression becomes $27\times\frac{1}{x^{18}}\times y^{12}=\frac{27y^{12}}{x^{18}}$

Answer:

$\frac{27y^{12}}{x^{18}}$