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Question
section 3.6: additional integr
score: 40/60 answered: 4/6
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question 5
compute the given integral.
$$ int x ^ { 4 } ln x d x = $$
Step1: Use integration by parts formula
The integration by parts formula is \(\int u\mathrm{d}v=uv - \int v\mathrm{d}u\). Let \(u = \ln x\), then \(\mathrm{d}u=\frac{1}{x}\mathrm{d}x\). Let \(\mathrm{d}v=x^{4}\mathrm{d}x\), then \(v=\frac{x^{5}}{5}\).
Step2: Apply the formula
$$
LATEXBLOCK0
$$
Step3: Integrate \(x^{4}\)
We know that \(\int x^{n}\mathrm{d}x=\frac{x^{n + 1}}{n+1}+C\) (\(n
eq - 1\)). So \(\int x^{4}\mathrm{d}x=\frac{x^{5}}{5}+C\).
$$
LATEXBLOCK1
$$
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\(\frac{x^{5}}{5}\ln x-\frac{x^{5}}{25}+C\)