Question

at a school fair, a person can go on up to 7 rides. draw a number line to represent the number of rides a person could go on. any value less than or equal to 7 r ≤ 7

Explanation:

Step1: Identify the inequality

The number of rides \( r \) satisfies \( r \leq 7 \), where \( r \) is a non - negative integer (since you can't go on a negative number of rides) and \( r\geq0 \).

Step2: Mark the critical point on the number line

On the given number line, find the position of 7. Since the inequality is \( r\leq7 \), we use a closed circle (or filled - in dot) at 7 to indicate that 7 is included in the solution set.

Step3: Draw the arrow for the solution set

We draw an arrow starting from the closed circle at 7 and going to the left (towards the smaller numbers) to represent all the numbers less than or equal to 7. Also, we consider the non - negative nature of the number of rides, so the relevant part of the number line is from 0 (or the leftmost relevant point) up to and including 7, with the arrow extending left from 7.

Answer:

To represent \( r\leq7 \) (where \( r \) is the number of rides, a non - negative integer) on the number line:

1. Place a closed circle at the point labeled 7 on the number line (to show that 7 is included in the set of possible number of rides).
2. Draw an arrow starting from the closed circle at 7 and pointing to the left (towards 0, 1, 2, 3, 4, 5, 6 and beyond in the left - ward direction) to represent all values of \( r \) that are less than or equal to 7.