Question

sampling vanability in the sample proportion quick check
use the table to answer the question
the table shows the numbers of the student with at least one pet.
jal nigah surveyed four different classes at her school to determine how many students had at least one pet at home. the preceding table summarizes the survey data. in which sample did the greatest proportion of students have a pet?
(1 point)

Explanation:

Step1: Calculate proportion for Sample 1

Proportion = $\frac{\text{Number of students with pet}}{\text{Total students}} = \frac{11}{18} \approx 0.611$

Step2: Calculate proportion for Sample 2

Proportion = $\frac{12}{22} \approx 0.545$

Step3: Calculate proportion for Sample 3

Proportion = $\frac{11}{17} \approx 0.647$

Step4: Calculate proportion for Sample 4

Proportion = $\frac{19}{18} \approx 1.056$ (Wait, this seems off. Wait, the total students in sample 4 is 18? And number with pet is 19? That can't be. Wait, maybe a typo? Wait, maybe sample 4: total students 18, number with pet 19? That's impossible. Wait, maybe it's 9? Let me check again. The table: sample 4, total students 18, number with at least 1 pet: 09? Maybe 9? If it's 9, then proportion is $\frac{9}{18}=0.5$. But if it's 19, that's more than total, which is impossible. So maybe a typo, but assuming the numbers as given: sample 1: 11/18≈0.611, sample 2:12/22≈0.545, sample 3:11/17≈0.647, sample 4:19/18≈1.056 (invalid, but maybe a typo, like 9). But if we take the numbers as given, sample 4 has 19/18 which is more than 1, impossible. So maybe a typo, sample 4: number with pet 9. Then 9/18=0.5. Then sample 3:11/17≈0.647, sample 1:11/18≈0.611, sample 2:12/22≈0.545, sample 4:9/18=0.5. Then the greatest proportion is sample 3? Wait, but the options: sample number 1, sample number 1 (duplicate?), sample number 4, sample number 3? Wait, the options are: sample number 1, sample number 1 (maybe a typo, sample number 3?), sample number 4, sample number 3? Wait, let's recalculate with correct numbers. Let's check the table again:

Sample 1: Total 18, Pet 11 → 11/18 ≈ 0.611

Sample 2: Total 22, Pet 12 → 12/22 ≈ 0.545

Sample 3: Total 17, Pet 11 → 11/17 ≈ 0.647

Sample 4: Total 18, Pet 19 → Impossible, so maybe 9 (09). Then 9/18 = 0.5

So the greatest proportion is sample 3 (11/17 ≈0.647), then sample 1 (≈0.611), then sample 2, then sample 4. But the options: if sample 4 is 19/18 (invalid), but maybe the original table has sample 4: total 19, pet 18? No. Wait, maybe the user made a typo. But assuming the numbers as given, even though sample 4 has more pets than total, which is impossible, but if we take 19/18, it's more than 1, which is impossible. So maybe a typo, sample 4: pet 19 is a typo, should be 9. Then sample 3: 11/17 ≈0.647, sample 1:11/18≈0.611, sample 2:12/22≈0.545, sample 4:9/18=0.5. Then the greatest is sample 3. But the options: sample number 3? Let's check the options again. The options are:

○ sample number 1

○ sample number 1 (maybe sample number 3?)

○ sample number 4

○ sample number 3

Ah, maybe the second option is sample number 3. So the correct answer is sample number 3.

Answer:

Sample number 3 (assuming the options include sample number 3, and the calculation shows sample 3 has the greatest proportion among valid samples, considering possible typo in sample 4's pet count)