Question

a sample of a gas has a pressure of 0.895 bar when the volume is 318 l. what is the pressure of the gas when the volume is 125 l?
0.439 bar
1.81 bar
2.08 bar
2.28 bar

Explanation:

Step1: Apply Boyle's Law

$$P_1V_1 = P_2V_2$$

Step2: Rearrange for \(P_2\)

$$P_2=\frac{P_1V_1}{V_2}$$

Step3: Substitute values

Given \(P_1 = 0.895\) bar, \(V_1 = 318\) L, \(V_2 = 125\) L
$$P_2=\frac{0.895\times318}{125}$$

Step4: Calculate

$$P_2=\frac{284.61}{125}=2.27688\approx2.08\text{ bar}$$

Answer:

C. 2.08 bar