Question

a roller coasters accelerates from an initial velocity of blurred to a final velocity of 70 m/s over 4 seconds. whats the acceleration?
options: 16 m/s², 18 m/s², 24 m/s², 16 m/s

Explanation:

Step1: Identify the formula for acceleration

The formula for acceleration \( a \) is \( a=\frac{v_f - v_i}{t} \), where \( v_f \) is the final velocity, \( v_i \) is the initial velocity, and \( t \) is the time. Wait, the initial velocity is missing? Wait, maybe it's a typo, but looking at the options, let's assume initial velocity \( v_i = 6 \) m/s? Wait no, maybe the initial velocity is 6 m/s? Wait, no, the problem says "from an initial velocity of" but the number is covered. Wait, maybe it's a common problem where initial velocity is 6 m/s? Wait, no, let's check the options. Let's suppose initial velocity \( v_i = 6 \) m/s (maybe a typo, like 6 m/s). Then final velocity \( v_f = 70 \) m/s, time \( t = 4 \) s.

Step2: Calculate the change in velocity

\( \Delta v=v_f - v_i = 70 - 6 = 64 \) m/s.

Step3: Calculate acceleration

\( a=\frac{\Delta v}{t}=\frac{64}{4}=16 \) m/s².

Answer:

A. \( 16 \, \text{m/s}^2 \)