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Question
rod traveled 21 miles on his bike ride. his average speed was 5.4 miles per hour. let t represent the number of hours he biked. write a division equation that can be used to find the number of hours he biked. use 21, 5.4, and t.
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Step1: Recall the speed formula
Speed is defined as distance divided by time, so \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \). Rearranging for time (or in this case, setting up the division equation), we know that distance is 21 miles, speed is 5.4 miles per hour, and time is \( t \) hours.
Step2: Set up the division equation
From the formula \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \), we can rewrite it as \( \text{Distance} \div \text{Speed} = \text{Time} \) (or \( \text{Distance} \div \text{Time} = \text{Speed} \), but we need to use the given values 21, 5.4, and \( t \)). Since distance is 21, speed is 5.4, and time is \( t \), the equation \( 21 \div 5.4 = t \) (or \( 21 \div t = 5.4 \)) is formed. But following the problem's request to use 21, 5.4, and \( t \) in the division equation \( \square \div \square = \square \), the correct setup is using distance divided by speed equals time, so \( 21 \div 5.4 = t \) (or if we consider \( \text{Distance} \div \text{Time} = \text{Speed} \), it would be \( 21 \div t = 5.4 \)). However, the problem says "write a division equation that can be used to find the number of hours he biked", so solving for \( t \) (time), we use \( \text{Time} = \text{Distance} \div \text{Speed} \), so \( 21 \div 5.4 = t \).
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\( 21 \div 5.4 = t \) (or if the blanks are filled as 21, 5.4, t in order: \( 21 \div 5.4 = t \))