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rod traveled 21 miles on his bike ride. his average speed was 5.4 miles…

Question

rod traveled 21 miles on his bike ride. his average speed was 5.4 miles per hour. let t represent the number of hours he biked. write a division equation that can be used to find the number of hours he biked. use 21, 5.4, and t.
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Explanation:

Step1: Recall the speed formula

Speed is defined as distance divided by time, so \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \). Rearranging for time (or in this case, setting up the division equation), we know that distance is 21 miles, speed is 5.4 miles per hour, and time is \( t \) hours.

Step2: Set up the division equation

From the formula \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \), we can rewrite it as \( \text{Distance} \div \text{Speed} = \text{Time} \) (or \( \text{Distance} \div \text{Time} = \text{Speed} \), but we need to use the given values 21, 5.4, and \( t \)). Since distance is 21, speed is 5.4, and time is \( t \), the equation \( 21 \div 5.4 = t \) (or \( 21 \div t = 5.4 \)) is formed. But following the problem's request to use 21, 5.4, and \( t \) in the division equation \( \square \div \square = \square \), the correct setup is using distance divided by speed equals time, so \( 21 \div 5.4 = t \) (or if we consider \( \text{Distance} \div \text{Time} = \text{Speed} \), it would be \( 21 \div t = 5.4 \)). However, the problem says "write a division equation that can be used to find the number of hours he biked", so solving for \( t \) (time), we use \( \text{Time} = \text{Distance} \div \text{Speed} \), so \( 21 \div 5.4 = t \).

Answer:

\( 21 \div 5.4 = t \) (or if the blanks are filled as 21, 5.4, t in order: \( 21 \div 5.4 = t \))