Question

in the reaction 2h₂ + o₂ → 2h₂o, what is the mole ratio of h₂ to h₂o? a. 2:1 b. 1:2 c. 2:2 d. 1:1

Explanation:

Step1: Analyze the chemical equation

The given equation is \(2H_2 + O_2
ightarrow2H_2O\).

Step2: Determine the mole ratio

The coefficient of \(H_2\) is \(2\) and the coefficient of \(H_2O\) is \(2\). The mole ratio of \(H_2\) to \(H_2O\) is \(\frac{\text{moles of }H_2}{\text{moles of }H_2O}=\frac{2}{2}=1:1\)

Answer:

A. \(2:1\) (This is incorrect as per the above calculation).
B. \(1:2\) (This is incorrect as per the above calculation).
C. \(2:2\) (Simplifies to \(1:1\), but the question asks for the ratio as per the given coefficients without simplifying in the context of the problem's options. Wait, no - looking at the equation \(2H_2 + O_2
ightarrow2H_2O\), the ratio of \(H_2\) (coefficient \(2\)) to \(H_2O\) (coefficient \(2\)) is \(2:2\) which simplifies to \(1:1\), but if we consider the coefficients as given in the equation without simplifying (since the options have \(2:2\) as an option), but wait no - wait the formula is \(2H_2\) and \(2H_2O\). The mole ratio of \(H_2\) to \(H_2O\) is \(2:2\) (if we take the coefficients directly). But wait, no - actually, in a chemical equation, the mole ratio is based on the stoichiometric coefficients. For \(H_2\) (coefficient \(2\)) and \(H_2O\) (coefficient \(2\)), the mole ratio \(H_2:H_2O = 2:2\) (but if we simplify \(2:2\) it's \(1:1\), but looking at the options, option \(a\) is \(2:1\) (wrong), \(b\) is \(1:2\) (wrong), \(c\) is \(2:2\) (correct as per coefficients), \(d\) is \(1:1\) (simplified). But in the context of the problem (since it's a multiple - choice with these options), and in chemical equations, when asked for the mole ratio as per the given equation (not simplified), the ratio of \(H_2\) (coefficient \(2\)) to \(H_2O\) (coefficient \(2\)) is \(2:2\).

So the answer is C. \(2:2\)