Question

questions 21 - 23 prompt
questions 21 - 23: determine the molecular equation, type of reaction, and the net ionic equation for the following reactions.
21 fill in the blank 4 points
molecular equation: nh₄cl(aq) + naoh(aq) → choose your answer...
type of reaction: choose your answer...
net ionic equation: choose your answer...

Explanation:

Step1: Write the molecular equation

When \(NH_4Cl(aq)\) reacts with \(NaOH(aq)\), the products are \(NH_3(g)\), \(H_2O(l)\) and \(NaCl(aq)\). The balanced molecular equation is \(NH_4Cl(aq)+NaOH(aq)=NH_3(g)+H_2O(l)+NaCl(aq)\)

Step2: Determine the type of reaction

This is an acid - base reaction (also known as a neutralization reaction in a broader sense). The ammonium ion (\(NH_4^{+}\)) acts as an acid (proton donor in the Bronsted - Lowry sense, as it can donate a proton to form \(NH_3\)) and \(OH^{-}\) from \(NaOH\) acts as a base.

Step3: Write the net ionic equation

First, write the complete ionic equation. \(NH_4^{+}(aq)+Cl^{-}(aq)+Na^{+}(aq)+OH^{-}(aq)=NH_3(g)+H_2O(l)+Na^{+}(aq)+Cl^{-}(aq)\). Then, cancel out the spectator ions (\(Na^{+}\) and \(Cl^{-}\)). The net ionic equation is \(NH_4^{+}(aq)+OH^{-}(aq)=NH_3(g)+H_2O(l)\)

Answer:

Molecular equation: \(NH_4Cl(aq)+NaOH(aq)=NH_3(g)+H_2O(l)+NaCl(aq)\)
Type of reaction: Acid - base reaction
Net ionic equation: \(NH_4^{+}(aq)+OH^{-}(aq)=NH_3(g)+H_2O(l)\)