Question

question
solve the following inequality for r. write your answer in simplest form.
-10r - 3 ≥ 10r + 6
answer attempt 1 out of 5
r < >
submit answer

Explanation:

Step1: Subtract \(10r\) from both sides

\(-10r - 3 - 10r \geq 10r + 6 - 10r\)
\(-20r - 3 \geq 6\)

Step2: Add 3 to both sides

\(-20r - 3 + 3 \geq 6 + 3\)
\(-20r \geq 9\)

Step3: Divide both sides by \(-20\) (and reverse the inequality sign)

\(\frac{-20r}{-20} \leq \frac{9}{-20}\)
\(r \leq -\frac{9}{20}\)

Answer:

\(r \leq -\frac{9}{20}\)