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question 2 (2 points) planar trigonal molecules like so₃ with __1__ red…

Question

question 2 (2 points)
planar trigonal molecules like so₃ with 1 reds are 2
symmetrical/asymmetrical and 3 nonpolar/polar
planar trigonal molecules like so₂s with 4 reds are 5
symmetrical/asymmetrical and 6 nonpolar/polar
bent molecules like so₂ with 7 reds are 8 symmetrical/asymmetrical and
9 nonpolar/polar
a. symmetrical b. asymmetrical c. nonpolar d. polar
e. 0 f. 1 g. 2 h. 3 i. 4

Explanation:

Brief Explanations
  • For \(SO_3\):
  • The number of regions of electron - density (REDS) around the central \(S\) atom is calculated. Using the formula \(n=\frac{V + M - C + A}{2}\) (where \(V\) is the valence electrons of the central atom, \(M\) is the number of monovalent atoms, \(C\) is the charge of cation, \(A\) is the charge of anion). For \(SO_3\), \(V = 6\) (valence electrons of \(S\)), \(M=0\), \(C = 0\), \(A = 0\). So \(n=\frac{6 + 0-0 + 0}{2}=3\).
  • In \(SO_3\), the three \(S - O\) bonds are identical and the molecule has a trigonal - planar geometry. The bond dipoles cancel out each other (because of symmetry), so it is symmetrical and non - polar.
  • For \(SO_2S\) (assuming it is a typo and you mean a molecule with a trigonal - planar geometry but different groups):
  • Let's assume a general trigonal - planar molecule with different substituents. The number of regions of electron - density around the central atom is still 3 (using the same electron - density formula as above). But due to different substituents, the bond dipoles do not cancel out. So it is asymmetrical and polar.
  • For \(SO_2\):
  • Using the formula \(n=\frac{V+M - C + A}{2}\), for \(SO_2\), \(V = 6\) (valence electrons of \(S\)), \(M = 0\), \(C=0\), \(A = 0\). But there is a lone pair. The number of regions of electron - density \(n = 3\) (two \(S - O\) bonds and one lone pair). The molecule has a bent geometry. The bond dipoles do not cancel out (because of the asymmetrical distribution of electron density due to the lone pair), so it is asymmetrical and polar.

Answer:

  1. H. 3
  2. A. symmetrical
  3. C. nonpolar
  4. H. 3
  5. B. asymmetrical
  6. D. polar
  7. H. 3
  8. B. asymmetrical
  9. D. polar