Question

question 4 (multiple choice worth 5 points) (04.01r lc) simplify \\(\frac{x^2 + 6x + 8}{x + 2}\\). \\(x^2 + 1\\) \\(x^2 - 1\\) \\(x - 4\\) \\(x + 4\\)

Explanation:

Step1: Factor the numerator

Factor \( x^2 + 6x + 8 \). We need two numbers that multiply to 8 and add to 6. Those numbers are 2 and 4. So, \( x^2 + 6x + 8=(x + 2)(x + 4) \).

Step2: Simplify the fraction

Substitute the factored form into the fraction: \( \frac{(x + 2)(x + 4)}{x + 2} \). Cancel out the common factor \( x + 2 \) (assuming \( x
eq - 2 \)), we get \( x + 4 \).

Answer:

D. \( x + 4 \)