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question 17
question 18
construct a truth table for the given compound statement: ~(p ∧ q) ∨ ~r
complete the truth table
| p | q | r | ~r | p ∧ q | ~(p ∧ q) | ~(p ∧ q) ∨ ~r |
| t | t | t |
question 19
question 20
Step1: Find negation of r
The negation of a true statement is false. When \(r = T\), \(\sim r=F\).
Step2: Find \(p\land q\)
The conjunction \(p\land q\) is true only when both \(p\) and \(q\) are true. Since \(p = T\) and \(q = T\), \(p\land q=T\).
Step3: Find \(\sim(p\land q)\)
The negation of a true statement is false. Since \(p\land q = T\), \(\sim(p\land q)=F\).
Step4: Find \(\sim(p\land q)\lor\sim r\)
The disjunction \(A\lor B\) is false only when both \(A\) and \(B\) are false. Here \(A=\sim(p\land q)=F\) and \(B = \sim r=F\), so \(\sim(p\land q)\lor\sim r=F\).
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| \(p\) | \(q\) | \(r\) | \(\sim r\) | \(p\land q\) | \(\sim(p\land q)\) | \(\sim(p\land q)\lor\sim r\) |
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