Question

question 3 how long would it take jesse with an acceleration of -2.50 m/s² to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?

Explanation:

Step1: Identify the kinematic equation

We use the kinematic equation \( v = v_0 + at \), where \( v \) is the final velocity, \( v_0 \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time. We want to find \( t \) when \( v = 0 \) (complete stop), \( v_0 = 13.5 \, \text{m/s} \), and \( a = -2.50 \, \text{m/s}^2 \).

Step2: Rearrange the equation to solve for \( t \)

Starting with \( v = v_0 + at \), we rearrange for \( t \):
\[
t = \frac{v - v_0}{a}
\]

Step3: Substitute the known values

Substitute \( v = 0 \), \( v_0 = 13.5 \, \text{m/s} \), and \( a = -2.50 \, \text{m/s}^2 \) into the equation:
\[
t = \frac{0 - 13.5}{-2.50}
\]

Step4: Calculate the time

First, calculate the numerator: \( 0 - 13.5 = -13.5 \). Then divide by the denominator:
\[
t = \frac{-13.5}{-2.50} = 5.4 \, \text{seconds}
\]

Answer:

The time it takes for Jesse to bring his bicycle to a complete stop is \( \boldsymbol{5.4 \, \text{seconds}} \).