Question

question 2 of 13
points possible: 1.00
suppose you are working with a naoh stock solution but you need a solution with a lower concentration for your experiment.
calculate the volume (in ml) of the 1.475 m stock naoh solution needed to prepare 250.0 ml of 0.1374 m dilute naoh solution.

Explanation:

Step1: Write the dilution formula

$C_1V_1 = C_2V_2$
where $C_1$ is the concentration of the stock solution, $V_1$ is the volume of the stock solution, $C_2$ is the concentration of the dilute solution, and $V_2$ is the volume of the dilute solution.

Step2: Rearrange the formula to solve for $V_1$

$V_1=\frac{C_2V_2}{C_1}$

Step3: Substitute the given values

$C_1 = 1.475\ M$, $C_2=0.1374\ M$, $V_2 = 250.0\ mL$
$V_1=\frac{0.1374\ M\times250.0\ mL}{1.475\ M}$

Step4: Calculate the value of $V_1$

$V_1=\frac{34.35}{1.475}\ mL = 23.3\ mL$

Answer:

$23.3\ mL$