Question

question 7 of 10
what is the perimeter of the octagon below?
a. 64 units
b. 62 units
c. 60 units
d. 66 units

Explanation:

Answer:

To find the perimeter of the octagon, we sum the lengths of all its sides. The side lengths are: \( AB = 6 \), \( BC = 4 \), \( CD = 8 \), \( DE = 3 \), \( EF = 4 \), \( FG = 17 \), \( GH = 10 \), and \( HA = 14 \).

Adding these lengths together:
\( 6 + 4 + 8 + 3 + 4 + 17 + 10 + 14 \)

Let's calculate step - by - step:
First, \( 6+4 = 10 \); then \( 10 + 8=18 \); then \( 18+3 = 21 \); then \( 21+4 = 25 \); then \( 25+17 = 42 \); then \( 42+10 = 52 \); then \( 52+14 = 66 \).

So the perimeter of the octagon is 66 units, and the answer is D. 66 units.