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question 2 of 10 suppose that, based on a sample, the 99.7% confidence …

Question

question 2 of 10
suppose that, based on a sample, the 99.7% confidence interval for the mean of a population is (59, 95). what was the mean of the sample?
a. 81
b. 73
c. 69
d. 77

Explanation:

Step1: Recall the formula for a confidence interval for the mean. The confidence interval is given by \((\bar{x} - E, \bar{x} + E)\), where \(\bar{x}\) is the sample mean and \(E\) is the margin of error. The sample mean is the midpoint of the confidence interval.

Step2: Calculate the midpoint of the interval \((59, 95)\). The midpoint (sample mean) is calculated as \(\frac{59 + 95}{2}\).

Step3: Compute the sum: \(59 + 95 = 154\). Then divide by 2: \(\frac{154}{2} = 77\). Wait, no, wait, 59 + 95 is 154? Wait, 59 + 95: 50 + 90 = 140, 9 + 5 = 14, so 140 +14=154. Then 154/2=77? Wait, but let's check again. Wait, 59 + 95: 59 + 95 = 154? Wait, 95 - 59 = 36, so the distance from 59 to 95 is 36, so the midpoint is 59 + 18 = 77? Wait, 36/2=18, 59+18=77. Wait, but let's recalculate 59 + 95: 59 + 95 = 154, 154/2=77. Wait, but let's check the options. Option D is 77. Wait, but wait, maybe I made a mistake. Wait, 59 + 95: 59 + 95 = 154? Wait, 95 + 59: 95 + 50 = 145, 145 +9=154. Yes. Then 154 divided by 2 is 77. So the sample mean is 77. Wait, but let's check again. Wait, the confidence interval is (59,95). The sample mean is the center of the interval, so \(\bar{x} = \frac{lower + upper}{2}\). So lower is 59, upper is 95. So \(\frac{59 + 95}{2} = \frac{154}{2} = 77\). So the sample mean is 77.

Answer:

D. 77