Question

question 7 of 10 jessica has a mass of 55 kg. she sleds down a hill that has a slope of 32°. what is the component of her weight that is along her direction of motion? a. 192 n b. 457 n c. 539 n d. 286 n

Explanation:

Step1: Calculate the weight

The weight formula is $F = mg$, where $m = 55\ kg$ and $g= 9.8\ m/s^{2}$. So $F=55\times9.8 = 539\ N$.

Step2: Find the component along the slope

The component of the weight along the direction of motion of the slope is $F_{parallel}=F\sin\theta$, with $\theta = 32^{\circ}$ and $F = 539\ N$. So $F_{parallel}=539\times\sin32^{\circ}\approx539\times0.5299 = 286\ N$.

Answer:

D. 286 N