Question

put these numbers in order from least to greatest.
18\frac{4}{8} -18\frac{24}{40} -\frac{32}{40} \frac{3}{6}

Explanation:

Step1: Simplify each number

• For \(18\frac{4}{8}\): Simplify the fraction \(\frac{4}{8}=\frac{1}{2}\), so \(18\frac{4}{8}=18.5\).
• For \(-18\frac{24}{40}\): Simplify \(\frac{24}{40}=\frac{3}{5} = 0.6\), so \(-18\frac{24}{40}=-18.6\).
• For \(-\frac{32}{40}\): Simplify to \(-\frac{4}{5}=-0.8\).
• For \(\frac{3}{6}\): Simplify to \(\frac{1}{2}=0.5\).

Step2: Compare the numbers

Negative numbers are less than positive numbers. Among negative numbers, the one with larger absolute value is smaller. So \(-18.6< - 0.8\) (since \(|-18.6| = 18.6\) and \(|-0.8|=0.8\), and \(18.6>0.8\)). Among positive numbers, \(0.5<18.5\) (since \(0.5=\frac{1}{2}\) and \(18.5 = 18\frac{1}{2}\)). Combining all, we have \(-18\frac{24}{40}<-\frac{32}{40}<\frac{3}{6}<18\frac{4}{8}\).

Answer:

\(-18\frac{24}{40}, -\frac{32}{40}, \frac{3}{6}, 18\frac{4}{8}\)