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put the following equation of a line into slope-intercept form, simplif…

Question

put the following equation of a line into slope-intercept form, simplifying all fractions.
2x + 2y = -8

Explanation:

Step1: Recall slope - intercept form

The slope - intercept form of a line is \(y=mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. We need to solve the given equation \(2x + 2y=-8\) for \(y\).

Step2: Isolate the \(y\) - term

Subtract \(2x\) from both sides of the equation:
\(2y=-2x - 8\)

Step3: Solve for \(y\)

Divide each term in the equation \(2y=-2x - 8\) by \(2\):
\(y=\frac{-2x}{2}+\frac{-8}{2}\)
Simplify the fractions:
\(y=-x - 4\)

Answer:

\(y=-x - 4\)