Question

predict the products of the reaction below. that is, complete the right - hand s

$\ce{hno_{3} + ba(oh)_{2}->\square}$

Explanation:

Step1: Identify the reaction type

This is an acid - base neutralization reaction. In an acid - base neutralization reaction, an acid (\(HNO_3\)) reacts with a base (\(Ba(OH)_2\)) to form a salt and water.

Step2: Write the general form of the reaction

The general form of an acid - base reaction is \(acid+base
ightarrow salt + water\). For \(HNO_3\) (nitric acid) and \(Ba(OH)_2\) (barium hydroxide), the \(H^+\) from \(HNO_3\) combines with \(OH^-\) from \(Ba(OH)_2\) to form \(H_2O\), and the \(Ba^{2 +}\) from \(Ba(OH)_2\) combines with \(NO_3^-\) from \(HNO_3\) to form the salt.

Step3: Balance the chemical equation

The un - balanced equation is \(HNO_3+Ba(OH)_2
ightarrow Ba(NO_3)_2 + H_2O\).
Count the number of atoms:

• For \(H\): Left side has \(1 + 2=3\) (from \(HNO_3\) and \(Ba(OH)_2\)), right side has \(2\) (from \(H_2O\)).
• For \(N\): Left side has \(1\), right side has \(2\) (from \(Ba(NO_3)_2\)).
• For \(O\): Left side has \(3 + 2=5\) (from \(HNO_3\) and \(Ba(OH)_2\)), right side has \(6 + 1 = 7\) (from \(Ba(NO_3)_2\) and \(H_2O\)).
• For \(Ba\): Left side has \(1\), right side has \(1\).

Multiply \(HNO_3\) by \(2\) and \(H_2O\) by \(2\) to balance the equation. The balanced equation is \(2HNO_3+Ba(OH)_2
ightarrow Ba(NO_3)_2 + 2H_2O\).

Answer:

\(2HNO_3+Ba(OH)_2
ightarrow Ba(NO_3)_2 + 2H_2O\)