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practice: balancing equations #1 show all work on a separate sheet of p…

Question

practice: balancing equations #1
show all work on a separate sheet of paper. place coefficients (not answers) in the blanks provided. you can leave coefficients of \1\ blank.

  1. _h₂ + _o₂ → ___h₂o
  2. _h₃po₄ + _koh → _k₃po₄ + _h₂o
  3. _k + _b₂o₃ → _k₂o + _b
  4. _hcl + _naoh → _nacl + _h₂o
  5. _na + _nano₃ → _na₂o + _n₂
  6. _c + _s₈ → ___cs₂
  7. _na + _o₂ → ___na₂o₂
  8. _n₂ + _o₂ → ___n₂o₅
  9. _h₃po₄ + _mg(oh)₂ → _mg₃(po₄)₂ + _h₂o
  10. _naoh + _h₂co₃ → _na₂co₃ + _h₂o
  11. _koh + _hbr → _kbr + _h₂o
  12. _h₂ + _o₂ → ___h₂o₂
  13. _na + _o₂ → ___na₂o
  14. _al(oh)₃ + _h₂co₃ → _al₂(co₃)₃ + _h₂o
  15. _al + _s₈ → ___al₂s₃
  16. _cs + _n₂ → ___cs₃n
  17. _mg + _cl₂ → ___mgcl₂
  18. _rb + _rbno₃ → _rb₂o + _n₂
  19. _c₆h₆ + _o₂ → _co₂ + _h₂o
  20. _n₂ + _h₂ → ___nh₃

reactions unit

Explanation:

Step1: Balance hydrogen and oxygen in $H_2 + O_2

ightarrow H_2O$
We need 2 moles of $H_2$ and 1 mole of $O_2$ to get 2 moles of $H_2O$. So the balanced equation is $2H_2+O_2
ightarrow2H_2O$.

Step2: Balance $H_3PO_4 + KOH

ightarrow K_3PO_4 + H_2O$
We need 1 mole of $H_3PO_4$ and 3 moles of $KOH$ to get 1 mole of $K_3PO_4$ and 3 moles of $H_2O$. So the balanced equation is $H_3PO_4 + 3KOH
ightarrow K_3PO_4+3H_2O$.

Step3: Balance $K + B_2O_3

ightarrow K_2O + B$
We need 6 moles of $K$ and 1 mole of $B_2O_3$ to get 3 moles of $K_2O$ and 2 moles of $B$. So the balanced equation is $6K + B_2O_3
ightarrow3K_2O+2B$.

Step4: Balance $HCl + NaOH

ightarrow NaCl + H_2O$
We need 1 mole of $HCl$ and 1 mole of $NaOH$ to get 1 mole of $NaCl$ and 1 mole of $H_2O$. So the balanced equation is $HCl + NaOH
ightarrow NaCl+H_2O$.

Step5: Balance $Na + NaNO_3

ightarrow Na_2O + N_2$
We need 10 moles of $Na$ and 2 moles of $NaNO_3$ to get 6 moles of $Na_2O$ and 1 mole of $N_2$. So the balanced equation is $10Na+2NaNO_3
ightarrow6Na_2O + N_2$.

Step6: Balance $C + S_8

ightarrow CS_2$
We need 4 moles of $C$ and 1 mole of $S_8$ to get 4 moles of $CS_2$. So the balanced equation is $4C+S_8
ightarrow4CS_2$.

Step7: Balance $Na + O_2

ightarrow Na_2O_2$
We need 2 moles of $Na$ and 1 mole of $O_2$ to get 1 mole of $Na_2O_2$. So the balanced equation is $2Na+O_2
ightarrow Na_2O_2$.

Step8: Balance $N_2 + O_2

ightarrow N_2O_5$
We need 2 moles of $N_2$ and 5 moles of $O_2$ to get 2 moles of $N_2O_5$. So the balanced equation is $2N_2 + 5O_2
ightarrow2N_2O_5$.

Step9: Balance $H_3PO_4 + Mg(OH)_2

ightarrow Mg_3(PO_4)_2 + H_2O$
We need 2 moles of $H_3PO_4$ and 3 moles of $Mg(OH)_2$ to get 1 mole of $Mg_3(PO_4)_2$ and 6 moles of $H_2O$. So the balanced equation is $2H_3PO_4+3Mg(OH)_2
ightarrow Mg_3(PO_4)_2 + 6H_2O$.

Step10: Balance $NaOH + H_2CO_3

ightarrow Na_2CO_3 + H_2O$
We need 2 moles of $NaOH$ and 1 mole of $H_2CO_3$ to get 1 mole of $Na_2CO_3$ and 2 moles of $H_2O$. So the balanced equation is $2NaOH + H_2CO_3
ightarrow Na_2CO_3+2H_2O$.

Step11: Balance $KOH + HBr

ightarrow KBr + H_2O$
We need 1 mole of $KOH$ and 1 mole of $HBr$ to get 1 mole of $KBr$ and 1 mole of $H_2O$. So the balanced equation is $KOH + HBr
ightarrow KBr+H_2O$.

Step12: Balance $H_2 + O_2

ightarrow H_2O_2$
We need 1 mole of $H_2$ and 1 mole of $O_2$ to get 1 mole of $H_2O_2$. So the balanced equation is $H_2+O_2
ightarrow H_2O_2$.

Step13: Balance $Na + O_2

ightarrow Na_2O$
We need 4 moles of $Na$ and 1 mole of $O_2$ to get 2 moles of $Na_2O$. So the balanced equation is $4Na+O_2
ightarrow2Na_2O$.

Step14: Balance $Al(OH)_3 + H_2CO_3

ightarrow Al_2(CO_3)_3 + H_2O$
We need 2 moles of $Al(OH)_3$ and 3 moles of $H_2CO_3$ to get 1 mole of $Al_2(CO_3)_3$ and 6 moles of $H_2O$. So the balanced equation is $2Al(OH)_3+3H_2CO_3
ightarrow Al_2(CO_3)_3 + 6H_2O$.

Step15: Balance $Al + S_8

ightarrow Al_2S_3$
We need 16 moles of $Al$ and 3 moles of $S_8$ to get 8 moles of $Al_2S_3$. So the balanced equation is $16Al+3S_8
ightarrow8Al_2S_3$.

Step16: Balance $Cs + N_2

ightarrow Cs_3N$
We need 6 moles of $Cs$ and 1 mole of $N_2$ to get 2 moles of $Cs_3N$. So the balanced equation is $6Cs+N_2
ightarrow2Cs_3N$.

Step17: Balance $Mg + Cl_2

ightarrow MgCl_2$
We need 1 mole of $Mg$ and 1 mole of $Cl_2$ to get 1 mole of $MgCl_2$. So the balanced equation is $Mg + Cl_2
ightarrow MgCl_2$.

Step18: Balance $Rb + RbNO_3

ightarrow Rb_2O + N_2$
We need 10 moles of $Rb$ and 2 moles of $RbNO_3$ to get 6 moles of $Rb_2O$ and 1 mole of $N_2$. So the balanced equation is $10Rb+2RbNO_3
igh…

Answer:

  1. $2H_2+O_2

ightarrow2H_2O$

  1. $H_3PO_4 + 3KOH

ightarrow K_3PO_4+3H_2O$

  1. $6K + B_2O_3

ightarrow3K_2O+2B$

  1. $HCl + NaOH

ightarrow NaCl+H_2O$

  1. $10Na+2NaNO_3

ightarrow6Na_2O + N_2$

  1. $4C+S_8

ightarrow4CS_2$

  1. $2Na+O_2

ightarrow Na_2O_2$

  1. $2N_2 + 5O_2

ightarrow2N_2O_5$

  1. $2H_3PO_4+3Mg(OH)_2

ightarrow Mg_3(PO_4)_2 + 6H_2O$

  1. $2NaOH + H_2CO_3

ightarrow Na_2CO_3+2H_2O$

  1. $KOH + HBr

ightarrow KBr+H_2O$

  1. $H_2+O_2

ightarrow H_2O_2$

  1. $4Na+O_2

ightarrow2Na_2O$

  1. $2Al(OH)_3+3H_2CO_3

ightarrow Al_2(CO_3)_3 + 6H_2O$

  1. $16Al+3S_8

ightarrow8Al_2S_3$

  1. $6Cs+N_2

ightarrow2Cs_3N$

  1. $Mg + Cl_2

ightarrow MgCl_2$

  1. $10Rb+2RbNO_3

ightarrow6Rb_2O + N_2$

  1. $2C_6H_6+15O_2

ightarrow12CO_2 + 6H_2O$

  1. $N_2+3H_2

ightarrow2NH_3$