Question

the poh of a solution is 10.75. what is the concentration of oh^- ions in the solution? use oh^-=10^{-poh}. 1.075×10^2 m 1.778×10^{-11} m 3.162×10^{-108} m 5.623×10^{10} m

Explanation:

Step1: Sustituir el valor de pOH en la fórmula

Dado que \( [OH^-]=10^{-pOH} \) y \( pOH = 10.75 \), entonces \( [OH^-]=10^{- 10.75} \).

Step2: Reescribir el exponente

\( 10^{-10.75}=10^{-(10 + 0.75)}=10^{-10}\times10^{-0.75} \).

Step3: Calcular \( 10^{-0.75} \)

\( 10^{-0.75}\approx1.778 \) (ya que \( 10^{-0.75}=\frac{1}{10^{0.75}} \) y \( 10^{0.75}\approx5.623 \)).

Step4: Calcular el valor final

\( 10^{-10}\times1.778 = 1.778\times10^{-11}\text{ M} \).

Answer:

B. \( 1.778\times 10^{-11}\text{ M} \)