Question

in peas, yellow seed color (y) is dominant to green seed color (y). a homozygous green seed pea plant is crossed with a heterozygous yellow seed pea plant. what is the predicted phenotypic ratio of the offspring based on seed color? 50 percent yellow, 50 percent green 50 percent yy, 50 percent yy 100 percent yellow, 0 percent green 100 percent yy, 0 percent yy

Explanation:

Step1: Determine the genotypes of the parents

A homozygous green - seed pea plant has the genotype \(yy\). A heterozygous yellow - seed pea plant has the genotype \(Yy\).

Step2: Set up the Punnett square

The possible gametes of the \(yy\) plant are all \(y\). The possible gametes of the \(Yy\) plant are \(Y\) and \(y\).

	\(Y\)	\(y\)

Step3: Analyze the phenotypes

Since \(Y\) (yellow) is dominant over \(y\) (green), \(Yy\) has a yellow phenotype and \(yy\) has a green phenotype. There are 2 \(Yy\) (yellow) and 2 \(yy\) (green) in the Punnett square. The phenotypic ratio is calculated as \(\frac{number\ of\ yellow - seeded\ offspring}{total\ number\ of\ offspring}:\frac{number\ of\ green - seeded\ offspring}{total\ number\ of\ offspring}\). The number of yellow - seeded offspring \(n(Yy)=2\), the number of green - seeded offspring \(n(yy) = 2\), and the total number of offspring \(n = 4\). The ratio of yellow - seeded to green - seeded offspring is \(\frac{2}{4}:\frac{2}{4}=1:1\), which is 50 percent yellow and 50 percent green.

Answer:

50 percent yellow, 50 percent green