QUESTION IMAGE
Question
part a
complete the table. use one of the approximate values for π discussed in class (for example 3.14, 22/7, 3.1416) and round to the nearest whole number.
hula hoop: diameter = 35 in, circumference = blank in
circular pond: diameter = blank ft, circumference = 556 ft
magnifying glass: diameter = 5.2 cm, circumference = blank cm
car tire: diameter = blank in, circumference = 71.6 in
Step1: Calculate the circumference of the Hula Hoop
The formula for the circumference of a circle is \(C = \pi d\). Given \(d = 35\) in and using \(\pi=\frac{22}{7}\).
\(C=\frac{22}{7}\times35\)
\(C = 22\times5=110\) in
Step2: Calculate the diameter of the Circular Pond
Using the formula \(C=\pi d\), we can solve for \(d\). Given \(C = 556\) ft and \(\pi=\frac{22}{7}\).
\(d=\frac{C}{\pi}=\frac{556}{\frac{22}{7}}=\frac{556\times7}{22}=\frac{3892}{22}\approx177\) ft
Step3: Calculate the circumference of the Magnifying Glass
Using \(C=\pi d\), with \(d = 5.2\) cm and \(\pi = 3.14\).
\(C=3.14\times5.2=16.328\approx16\) cm
Step4: Calculate the diameter of the Car Tire
Using \(d=\frac{C}{\pi}\), with \(C = 71.6\) in and \(\pi=\frac{22}{7}\).
\(d=\frac{71.6}{\frac{22}{7}}=\frac{71.6\times7}{22}=\frac{501.2}{22}\approx23\) in
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| Object | Diameter | Circumference |
|---|---|---|
| Circular Pond | \(177\) ft | \(556\) ft |
| Magnifying Glass | \(5.2\) cm | \(16\) cm |
| Car Tire | \(23\) in | \(71.6\) in |