Question

part b
add. express your answer as a polynomial in standard form.
(1 point)
$(3x^3 - 5x^2 + x + 7) + (x^2 + 3x + 7) = \square$

Explanation:

Step1: Remove parentheses

Remove the parentheses from \((3x^{3}-5x^{2}+x + 7)+(x^{2}+3x + 7)\) to get \(3x^{3}-5x^{2}+x + 7+x^{2}+3x + 7\).

Step2: Combine like terms

• For \(x^{3}\) term: \(3x^{3}\) (no other \(x^{3}\) terms).
• For \(x^{2}\) terms: \(-5x^{2}+x^{2}=-4x^{2}\).
• For \(x\) terms: \(x + 3x = 4x\).
• For constant terms: \(7+7 = 14\).

Combine these results: \(3x^{3}-4x^{2}+4x + 14\).

Answer:

\(3x^{3}-4x^{2}+4x + 14\)