Question

parents that are heterozygous for having freckles (dominant) are crossed. which correctly describes their offspring?
twenty - five percent have freckles.
twenty - five percent are ff.
seventy - five percent have freckles.
seventy - five percent are ff.

Explanation:

1. Let the allele for freckles be \( F \) (dominant) and for no freckles be \( f \) (recessive). Heterozygous parents have genotype \( Ff \).
2. When \( Ff\times Ff \) is done, the Punnett square gives genotypes: \( FF \) (25%), \( Ff \) (50%), \( ff \) (25%).
3. Phenotype: \( FF \) and \( Ff \) have freckles. So total with freckles: \( 25\% + 50\%=75\% \), and \( Ff \) is 50%. So "Seventy - five percent have freckles" is correct.

Answer:

C. Seventy - five percent have freckles. (Assuming the options are labeled as A, B, C, D with A: Twenty - five percent have freckles, B: Twenty - five percent are Ff, C: Seventy - five percent have freckles, D: Seventy - five percent are Ff)