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number 10 (-3x^{-3}y^{-2})(2x^{4}y^{5})

Question

number 10
(-3x^{-3}y^{-2})(2x^{4}y^{5})

Explanation:

Step1: Multiply the coefficients

Multiply -3 and 2: $-3\times2 = -6$

Step2: Multiply the x-terms

Use the rule $a^m\times a^n = a^{m + n}$. For $x^{-3}$ and $x^4$: $x^{-3}\times x^4 = x^{-3 + 4}=x^{1}=x$

Step3: Multiply the y-terms

Use the same exponent rule. For $y^{-2}$ and $y^5$: $y^{-2}\times y^5 = y^{-2 + 5}=y^{3}$

Step4: Combine the results

Multiply the coefficient, x - term, and y - term together: $-6\times x\times y^{3}=-6xy^{3}$

Answer:

$-6xy^{3}$