QUESTION IMAGE
Question
do now
chemistry - date:
directions: silently and independently answer the questions below in complete sentences. be
prepared to share your answers and participate in a whole - class discussion.
- what does the formula ( q = mcdelta t ) describe?
sentence starter: this formula shows....
- define specific heat capacity in your own words.
sentence starter: the amount of energy needed to....
- water has a specific heat capacity of ( 4.18 j/gcdot k ). if you add ( 209 j ) of heat to ( 10 g ) of
water, how much will its temperature increase?
1.
The formula \( q = mC\Delta T\) is used in thermochemistry. Here, \(q\) represents the heat energy transferred, \(m\) is the mass of the substance, \(C\) is the specific heat capacity (a property of the substance that tells how much heat is needed to change the temperature of a unit mass of the substance by 1 degree), and \(\Delta T\) is the change in temperature. So, this formula shows the relationship between the heat energy absorbed or released (\(q\)) by a substance, its mass (\(m\)), its specific heat capacity (\(C\)), and the change in its temperature (\(\Delta T\)).
Specific heat capacity is a fundamental concept in thermodynamics. When we talk about it, we consider the energy aspect. The key is that it's about a unit - mass (like 1 gram or 1 kilogram) of a substance and a 1 - unit change in temperature (like 1 Kelvin or 1 degree Celsius). The sentence starter “The amount of energy needed to...” can be completed by specifying these conditions.
Step1: Rearrange the formula \(q = mC\Delta T\) for \(\Delta T\)
We know that \(q = mC\Delta T\). To find \(\Delta T\), we can rewrite the formula as \(\Delta T=\frac{q}{mC}\)
Step2: Substitute the given values into the formula
Given \(q = 209\space J\), \(m = 10\space g\), and \(C=4.18\space J/g\cdot K\)
Substitute into \(\Delta T=\frac{q}{mC}\), we get \(\Delta T=\frac{209\space J}{10\space g\times4.18\space J/g\cdot K}\)
Step3: Calculate the value of \(\Delta T\)
First, calculate the denominator \(10\space g\times4.18\space J/g\cdot K = 41.8\space J/K\)
Then \(\Delta T=\frac{209\space J}{41.8\space J/K}=5\space K\)
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
This formula shows the relationship between the heat energy absorbed or released (\(q\)) by a substance, its mass (\(m\)), its specific heat capacity (\(C\)), and the change in its temperature (\(\Delta T\)).