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Question
multiply. (8y + 3)(8y - 3) simplify your answer.
Step1: Apply difference - of - squares formula
We use the formula $(a + b)(a - b)=a^{2}-b^{2}$. Here $a = 8y$ and $b = 3$.
$(8y + 3)(8y - 3)=(8y)^{2}-3^{2}$
Step2: Simplify each term
$(8y)^{2}=8^{2}\times y^{2}=64y^{2}$ and $3^{2}=9$.
So, $(8y)^{2}-3^{2}=64y^{2}-9$
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$64y^{2}-9$