Question

6 multiple choice 2 points by what mechanism does cyclohexanol react when treated in sulfuric acid and what compound results? e1; methoxycyclohexane e2; cyclohexene e1; cyclohexene e2; methoxycyclohexane sn1; methoxycyclohexane previous

Explanation:

Step1: Analyze reaction type

Cyclohexanol is a secondary alcohol. In sulfuric acid (a strong acid), alcohols undergo elimination reactions. Since it's a secondary alcohol and the reaction conditions (heating, acidic medium) favor a step - by - step process (not a concerted one like E2), it follows the E1 mechanism.

Step2: Determine product

The elimination of water (\(H_2O\)) from cyclohexanol (\(C_6H_{11}OH\)) gives cyclohexene (\(C_6H_{10}\)). Methoxycyclohexane (\(C_6H_{11}OCH_3\)) would be a substitution product, but the reaction conditions (acid - catalyzed elimination, not a nucleophilic substitution environment with a suitable nucleophile like \(CH_3O^-\)) rule out substitution products. So the product is cyclohexene.

Answer:

C. E1; cyclohexene