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Question
6 multiple choice 1 point simplify the expression. write your answer using only positive exponents. $x^{-7}$ $\frac{1}{x^7}$ $7x$ $-\frac{7}{x}$ $-7x$ clear my selection
Step1: Recall the negative exponent rule
The rule for negative exponents is \( a^{-n} = \frac{1}{a^{n}} \) for any non - zero real number \( a \) and positive integer \( n \).
Step2: Apply the rule to \( x^{-7} \)
Here, \( a = x \) and \( n = 7 \). Using the negative exponent rule, we have \( x^{-7}=\frac{1}{x^{7}} \).
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A. \(\frac{1}{x^{7}}\)