Question

multiple choice 1 point assume that genes a and b are not linked. if the probability of allele a in a gamete is 1/2 and the probability of allele b in a gamete is 1/2, then the probability that both a and b are in the same gamete is 1/2 × 1/2 1/2 + 1/2 \sqrt{\frac{1}{2}} |1/2 - 1/2|

Explanation:

Step1: Identify the principle

Since genes A and B are not linked, the events of allele A being in a gamete and allele B being in a gamete are independent events. For independent events, the probability of both events occurring is the product of their individual probabilities.

Step2: Apply the multiplication rule

The probability of allele A in a gamete is $\frac{1}{2}$ and the probability of allele B in a gamete is $\frac{1}{2}$. Using the multiplication rule for independent events $P(A\cap B)=P(A)\times P(B)$, we substitute the values: $P(A\cap B)=\frac{1}{2}\times\frac{1}{2}$.

Answer:

The correct option is the one with $\frac{1}{2} \times \frac{1}{2}$ (the first option among the given choices, assuming the first option is $\frac{1}{2} \times \frac{1}{2}$).