Question

mr. piper is driving roddy and scott home from school. they both want to ride in the front seat. how can he make a fair decision about who rides in the front seat? select all of the correct answers. a. roll a number cube. if it lands on an even number, roddy wins. if it lands on an odd number, scott wins. b. flip a coin twice. if both tosses are heads, roddy wins. if one is heads and one is tails, scott wins. c. roll a number cube. if it lands on 1 or 2, roddy wins. if it lands on any other number, scott wins. d. put each persons name on a separate piece of paper in a bag. randomly draw the winning name.

Explanation:

A fair decision requires equal probability (50% chance) for each person.

• A: Number cube has 3 even (2,4,6) and 3 odd (1,3,5) numbers → equal chance.
• B: Coin twice has 4 outcomes: HH, HT, TH, TT. Roddy wins 1/4, Scott wins 2/4 → unequal.
• C: Roddy wins 2/6=1/3, Scott wins 4/6=2/3 → unequal.
• D: Two names, each has 1/2 chance → equal.

Answer:

A. Roll a number cube. If it lands on an even number, Roddy wins. If it lands on an odd number, Scott wins.
D. Put each person's name on a separate piece of paper in a bag. Randomly draw the winning name.