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x+(x+1)+(x+2)+(x+3)=26

Question

x+(x+1)+(x+2)+(x+3)=26

Explanation:

Step1: Simplify the left - hand side

First, we expand the left - hand side of the equation \(x+(x + 1)+(x + 2)+(x + 3)=26\).
When we remove the parentheses, we get \(x+x + 1+x + 2+x + 3\).
Then we combine like terms. The \(x\) terms: \(x+x+x+x = 4x\), and the constant terms: \(1 + 2+3=6\).
So the equation becomes \(4x+6 = 26\).

Step2: Solve for \(x\)

Subtract 6 from both sides of the equation \(4x+6 = 26\).
We have \(4x+6-6=26 - 6\), which simplifies to \(4x=20\).
Then divide both sides by 4: \(\frac{4x}{4}=\frac{20}{4}\), so \(x = 5\).

Answer:

\(x = 5\)